Dear fellows,

The files shared in replies of this discussion are also available at VU LMS content Library.

http://vulms.vu.edu.pk/Library/library.aspx

if you have any confusion about any example, you can ask in the replies of this discussion and we will try our best to solve it and clear our confusion. Also if you find any mistake in any example or you find a hard one, you can explain in the replies so that it will help others. 

:)

Good Luck. 

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Can anyone please explain me the example on page 47 lecture 8 ???

Examples of Lecture: 7

Page 39

Attachments:

Examples of Lecture: 8

Page 43 Example 2

Attachments:

Page 43 Example 3

Attachments:

Page 44

Attachments:

Page 45

Attachments:

Examples of Lecture: 13

Page 76, Example

Formula for "Equation of Normal Line"

So the answer for the equation of normal line will be:

x = 1 + 2t

y = -2 - 4t

z = 3 + 6t

Page 77, Example

Formula for "Equation of Normal Line"

So the answer for the equation of normal line will be:

x = 2 + 16t

y = -3 + 6t

z = 1 + 6t

Page 77, Example

Formula for "Equation of Normal Line"

So the answer for the equation of normal line will be:

x = 2 + 14t

y = 4 - 2t

z = 4 - t

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